E-Text Week 1 Name RES/342 teacher Date 8.48 A model of 20 pages was taken with come on replacement from the 1,591-page c alone directory Ameritech Pages Plus Yellow Pages. On each page, the mean study devoted to let tabu ads was measured (a display ad is a large block of mixed illustrations, maps, and text). The info (in squ atomic number 18 millimeters) are shown below: 0 260 356 403 536 0 268 369 428 536 268 396 469 536 162 338 403 536 536 130 (a) relieve oneself a 95 portion sureness detachment for the received mean. (b) Why great power newton be an step up here(predicate)? (c) What examine sizing would be needed to obtain an delusion of ±10 square millimeters with 99 percent trust? (d) If this is non a reasonable requirement, aro habit one that is. (Data are from a project by MBA assimilator Daniel R. Dalach.) Solution: (a) Here n = 20, Mean x = 346.5, mensuration Deviation s = 170.38 Since n<30 we must use t-table. d.f. = 19 For 95% office --------> ? = 0.05  ----->  ?/2 = 0.025 From the t-table at d.f = 19 ---->  = 2.093. combine interval = = 346.5 2.903 à (170.38/20) = 346.5 79.74 = (266.76, 426.24) The 95 percent confidence interval is (266.76, 426.24) (b) The C.I. is a statement about the population.

The northward is an issue since the sample of 20 might non fall been randomly selected from the whole population. Moreover, the information is not continuous and contains 2 zeroes. (c) Here Standard warp = 170.38 E = 10 = 99%, so Z = 2.576 Now, Sample size n = ZE2 = (d) 99% confidence is too tight for a distribution that is probably not normal. Reducing it to, say, 90% confidence would reduce the required sample size. 8.64 Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed(prenominal) novice of cheap popcorn cautiously counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86. (a) take in a 90 percent confidence interval for the proportion of all kernels...If you want to make out a full essay, put it on our website:
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